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There are 5 letters in MORER ( E1M3O1R1 )
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Definitions of morer in various dictionaries:
adj - (comparative of `much' used with mass noun s) a quantifier meaning greater in size or amount or extent or degree
adj - (comparative of `many' used with count noun s) quantifier meaning greater in number
MORER - In complex analysis, a branch of mathematics, Morera's theorem, named after Giacinto Morera, gives an important criterion for proving that a function...
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In complex analysis, a branch of mathematics, Morera's theorem, named after Giacinto Morera, gives an important criterion for proving that a function is holomorphic. * Morera's theorem states that a continuous, complex-valued function ƒ defined on an open set D in the complex plane that satisfies* * * * * * * * ∮ * * * * * * * γ * * * * f * ( * z * ) * * d * z * = * 0 * * * {\displaystyle \oint _{\gamma }f(z)\,dz=0} * for every closed piecewise C1 curve * * * * γ * * * {\displaystyle \gamma } * in D must be holomorphic on D. * The assumption of Morera's theorem is equivalent to that ƒ has an antiderivative on D. * The converse of the theorem is not true in general. A holomorphic function need not possess an antiderivative on its domain, unless one imposes additional assumptions. The converse does hold e.g. if the domain is simply connected; this is Cauchy's integral theorem, stating that the line integral of a holomorphic function along a closed curve is zero. * The standard counterexample is the function ƒ(z) = 1/z, which is holomorphic on ℂ − {0}. On any simply connected neighborhood U in ℂ − {0}, 1/z has an antiderivative defined by L(z) = ln(r) + iθ, where z = reiθ. Because of the ambiguity of θ up to the addition of any integer multiple of 2π, any continuous choice of θ on U will suffice to define an antiderivative of 1/z on U. (It is the fact that θ cannot be defined continuously on a simple closed curve containing the origin in its interior that is the root of why 1/z has no antiderivative on its entire domain ℂ − {0}.) And because the derivative of an additive constant is 0, any constant may be added to the antiderivative and it's still an antiderivative of 1/z. * In a certain sense, the 1/z counterexample is universal: For every analytic function that has no antiderivative on its domain, the reason for this is that 1/z itself does not have an antiderivative on ℂ − {0}. |