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prewe

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The answer PREWE has 0 possible clue(s) in existing crosswords.

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The word PREWE is NOT valid in any word game. (Sorry, you cannot play PREWE in Scrabble, Words With Friends etc)

There are 5 letters in PREWE ( E1P3R1W4 )

To search all scrabble anagrams of PREWE, to go: PREWE?

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Scrabble results that can be created with an extra letter added to PREWE

PEWTER WEEPER SPEWER

4 letters out of PREWE

EWER PEER PERE PREE WEEP WEER WERE

3 letters out of PREWE

ERE EWE PEE PER PEW REE REP WEE

2 letters out of PREWE

ER PE RE WE

Searching in Dictionaries ...

Definitions of prewe in various dictionaries:

PREWE - In set theory, a prewellordering is a binary relation ≤ {\displaystyle \leq } that is transitive, total,...

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Prewe might refer to
In set theory, a prewellordering is a binary relation
*
*
*
* ≤
*
*
* {\displaystyle \leq }
* that is transitive, total, and wellfounded (more precisely, the relation
*
*
*
* x
* ≤
* y
* ∧
* y
* ≰
* x
*
*
* {\displaystyle x\leq y\land y\nleq x}
* is wellfounded). In other words, if
*
*
*
* ≤
*
*
* {\displaystyle \leq }
* is a prewellordering on a set
*
*
*
* X
*
*
* {\displaystyle X}
* , and if we define
*
*
*
* ∼
*
*
* {\displaystyle \sim }
* by*
*
*
* x
* ∼
* y
*
* ⟺
*
* x
* ≤
* y
* ∧
* y
* ≤
* x
*
*
* {\displaystyle x\sim y\iff x\leq y\land y\leq x}
* then
*
*
*
* ∼
*
*
* {\displaystyle \sim }
* is an equivalence relation on
*
*
*
* X
*
*
* {\displaystyle X}
* , and
*
*
*
* ≤
*
*
* {\displaystyle \leq }
* induces a wellordering on the quotient
*
*
*
* X
*
* /
*
* ∼
*
*
* {\displaystyle X/\sim }
* . The order-type of this induced wellordering is an ordinal, referred to as the length of the prewellordering.
* A norm on a set
*
*
*
* X
*
*
* {\displaystyle X}
* is a map from
*
*
*
* X
*
*
* {\displaystyle X}
* into the ordinals. Every norm induces a prewellordering; if
*
*
*
* ϕ
* :
* X
* →
* O
* r
* d
*
*
* {\displaystyle \phi :X\to Ord}
* is a norm, the associated prewellordering is given by
*
*
*
*
* x
* ≤
* y
*
* ⟺
*
* ϕ
* (
* x
* )
* ≤
* ϕ
* (
* y
* )
*
*
* {\displaystyle x\leq y\iff \phi (x)\leq \phi (y)}
* Conversely, every prewellordering is induced by a unique regular norm (a norm
*
*
*
* ϕ
* :
* X
* →
* O
* r
* d
*
*
* {\displaystyle \phi :X\to Ord}
* is regular if, for any
*
*
*
* x
* ∈
* X
*
*
* {\displaystyle x\in X}
* and any
*
*
*
* α
* <
* ϕ
* (
* x
* )
*
*
* {\displaystyle \alpha <\phi (x)}
* , there is
*
*
*
* y
* ∈
* X
*
*
* {\displaystyle y\in X}
* such that
*
*
*
* ϕ
* (
* y
* )
* =
* α
*
*
* {\displaystyle \phi (y)=\alpha }
* ).
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