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culmina

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Definitions of culmina in various dictionaries:

CULMINA - In observational astronomy, the culmination of a celestial object (the Sun, the Moon, a planet, a star, or a deep-sky object) or constellation is eit...

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The upper ridge of a bird's bill.
A small region in the brain on the anterior surface of the cerebellum.

Culmina might refer to
In observational astronomy, the culmination of a celestial object (the Sun, the Moon, a planet, a star, or a deep-sky object) or constellation is either of two moments when it reaches the observer's meridian on the celestial sphere, on which it appears to move along a circular path over the course of a day, due to Earth's rotation. * As viewed from the surface of a terrestrial body, except its geographic poles, a celestial object passes through the meridian twice a day: once at its upper culmination, when it reaches its highest point as viewed from a given location on Earth, and once at its lower culmination, when it reaches its lowest point. The term culmination is often used to mean upper culmination.An object's altitude (A) in degrees at its upper culmination is equal to 90 subtracted by the observer's latitude (L) and added by the object's declination (δ): A = 90° − L + δ.

Culmina might refer to

In observational astronomy, the culmination of a celestial object (the Sun, the Moon, a planet, a star, or a deep-sky object) or constellation is either of two moments when it reaches the observer's meridian on the celestial sphere, on which it appears to move along a circular path over the course of a day, due to Earth's rotation.
* As viewed from the surface of a terrestrial body, except its geographic poles, a celestial object passes through the meridian twice a day: once at its upper culmination, when it reaches its highest point as viewed from a given location on Earth, and once at its lower culmination, when it reaches its lowest point. The term culmination is often used to mean upper culmination.An object's altitude (A) in degrees at its upper culmination is equal to 90 subtracted by the observer's latitude (L) and added by the object's declination (δ): A = 90° − L + δ.

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