Crossword Solver > found answer > TURNOVER (turn over)

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CROSSWORD
ANSWER

turnover

turn over

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The answer TURNOVER (turn over) has 105 possible clue(s) in existing crosswords.

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The word TURNOVER (turn over) is NOT valid in any word game. (Sorry, you cannot play TURNOVER (turn over) in Scrabble, Words With Friends etc)

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Definitions of turn over in various dictionaries:

noun - the ratio of the number of workers that had to be replaced in a given time period to the average number of workers

noun - a dish made by folding a piece of pastry over a filling

noun - the volume measured in dollars

more

Word Research / Anagrams and more ...

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Possible Crossword Clues
Switch sides
Apple treat
*Invalidate in appeals court
Pastry shop order
Gridiron boo-boo
Apple pastry
Fruit-filled pastry
Triangular pastry
Rev? O, there's the new page
Rev, O that's all the business you do

Possible Jeopardy Clues
While being grilled to death, St. Lawrence said, "please" do this; "I'm done on one side"

Turn over might refer to

Turn over might be related to
Turnover number has two different meanings: * In enzymology, turnover number (also termed kcat) is defined as the maximum number of chemical conversions of substrate molecules per second that a single catalytic site will execute for a given enzyme concentration * * * * [ * * E * * T * * * ] * * * {\displaystyle [E_{T}]} * . It can be calculated from the maximum reaction rate * * * * * V * * max * * * * * {\displaystyle V_{\max }} * and catalyst site concentration * * * * [ * * E * * T * * * ] * * * {\displaystyle [E_{T}]} * as follows: * * * * * k * * * c * a * t * * * * = * * * * V * * max * * * * [ * * E * * T * * * ] * * * * * * {\displaystyle k_{\mathrm {cat} }={\frac {V_{\max }}{[E_{T}]}}} * (See Michaelis-Menten kinetics).For example, carbonic anhydrase has a turnover number of 400,000 to 600,000 s−1, which means that each carbonic anhydrase molecule can produce up to 600,000 molecules of product (bicarbonate ions) per second.In other chemical fields, such as organometallic catalysis, turnover number (abbreviated TON) has a different meaning: the number of moles of substrate that a mole of catalyst can convert before becoming inactivated. An ideal catalyst would have an infinite turnover number in this sense, because it wouldn't ever be consumed, but in actual practice one often sees turnover numbers which go from 100 up to 40 million for catalase. The term turnover frequency (abbreviated TOF) is used to refer to the turnover per unit time, as in enzymology. For most relevant industrial applications, the turnover frequency is in the range of 10−2 - 102 s−1 (enzymes 103 - 107 s−1).[1] * Turnover frequency of catalase is maximum i.e. 4 X 107 s−1.

Turn over might be related to

Turnover number has two different meanings:
* In enzymology, turnover number (also termed kcat) is defined as the maximum number of chemical conversions of substrate molecules per second that a single catalytic site will execute for a given enzyme concentration
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* . It can be calculated from the maximum reaction rate
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* {\displaystyle k_{\mathrm {cat} }={\frac {V_{\max }}{[E_{T}]}}}
* (See Michaelis-Menten kinetics).For example, carbonic anhydrase has a turnover number of 400,000 to 600,000 s−1, which means that each carbonic anhydrase molecule can produce up to 600,000 molecules of product (bicarbonate ions) per second.In other chemical fields, such as organometallic catalysis, turnover number (abbreviated TON) has a different meaning: the number of moles of substrate that a mole of catalyst can convert before becoming inactivated. An ideal catalyst would have an infinite turnover number in this sense, because it wouldn't ever be consumed, but in actual practice one often sees turnover numbers which go from 100 up to 40 million for catalase. The term turnover frequency (abbreviated TOF) is used to refer to the turnover per unit time, as in enzymology. For most relevant industrial applications, the turnover frequency is in the range of 10−2 - 102 s−1 (enzymes 103 - 107 s−1).[1]
* Turnover frequency of catalase is maximum i.e. 4 X 107 s−1.

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