Welcome to Anagrammer Crossword Genius! Keep reading below to see if bigrams is an answer to any crossword puzzle or word game (Scrabble, Words With Friends etc). Scroll down to see all the info we have compiled on bigrams.
bigrams
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The answer BIGRAMS has 1 possible clue(s) in existing crosswords.
Searching in Word Games ...
The word BIGRAMS is NOT valid in any word game. (Sorry, you cannot play BIGRAMS in Scrabble, Words With Friends etc)
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Definitions of bigrams in various dictionaries:
noun - a word that is written with two letters in an alphabetic writing system
BIGRAMS - A bigram or digram is a sequence of two adj acent elements from a string of tokens, which are typically letters, syllables, or words. A bigram is an n...
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Keep reading for additional results and analysis below.
Possible Crossword Clues |
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* Pairs of consecutive letters |
Last Seen in these Crosswords & Puzzles |
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Nov 25 2018 Premier Sunday - King Feature Syndicate |
Bigrams might refer to |
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A Bigram or digram is a sequence of two adjacent elements from a string of tokens, which are typically letters, syllables, or words. A bigram is an n-gram for n=2. The frequency distribution of every bigram in a string is commonly used for simple statistical analysis of text in many applications, including in computational linguistics, cryptography, speech recognition, and so on. * Gappy bigrams or skipping bigrams are word pairs which allow gaps (perhaps avoiding connecting words, or allowing some simulation of dependencies, as in a dependency grammar). * Head word bigrams are gappy bigrams with an explicit dependency relationship. * Bigrams help provide the conditional probability of a token given the preceding token, when the relation of the conditional probability is applied:* * * * P * ( * * W * * n * * * * | * * * W * * n * − * 1 * * * ) * = * * * * P * ( * * W * * n * − * 1 * * * , * * W * * n * * * ) * * * P * ( * * W * * n * − * 1 * * * ) * * * * * * {\displaystyle P(W_{n}|W_{n-1})={P(W_{n-1},W_{n}) \over P(W_{n-1})}} * * That is, the probability * * * * P * ( * ) * * * {\displaystyle P()} * of a token * * * * * W * * n * * * * * {\displaystyle W_{n}} * given the preceding token * * * * * W * * n * − * 1 * * * * * {\displaystyle W_{n-1}} * is equal to the probability of their bigram, or the co-occurrence of the two tokens * * * * P * ( * * W * * n * − * 1 * * * , * * W * * n * * * ) * * * {\displaystyle P(W_{n-1},W_{n})} * , divided by the probability of the preceding token. |